LeetCode 1603. Design Parking System Solution in Java, C++, Python & More | Explanation + Code

CoderIndeed
0
1603. Design Parking System

Description

Design a parking system for a parking lot. The parking lot has three kinds of parking spaces: big, medium, and small, with a fixed number of slots for each size.

Implement the ParkingSystem class:

  • ParkingSystem(int big, int medium, int small) Initializes object of the ParkingSystem class. The number of slots for each parking space are given as part of the constructor.
  • bool addCar(int carType) Checks whether there is a parking space of carType for the car that wants to get into the parking lot. carType can be of three kinds: big, medium, or small, which are represented by 1, 2, and 3 respectively. A car can only park in a parking space of its carType. If there is no space available, return false, else park the car in that size space and return true.

 

Example 1:

Input
["ParkingSystem", "addCar", "addCar", "addCar", "addCar"]
[[1, 1, 0], [1], [2], [3], [1]]
Output
[null, true, true, false, false]

Explanation
ParkingSystem parkingSystem = new ParkingSystem(1, 1, 0);
parkingSystem.addCar(1); // return true because there is 1 available slot for a big car
parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car
parkingSystem.addCar(3); // return false because there is no available slot for a small car
parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied.

 

Constraints:

  • 0 <= big, medium, small <= 1000
  • carType is 1, 2, or 3
  • At most 1000 calls will be made to addCar

Solutions

Solution 1: Simulation

We use an array cnt of length 4 to represent the number of parking spaces for each type of car, where cnt[1], cnt[2], and cnt[3] represent the number of large, medium, and small parking spaces, respectively.

During initialization, we set cnt[1], cnt[2], and cnt[3] to the number of large, medium, and small parking spaces, respectively.

Each time a car parks, we check if there is a corresponding parking space in the parking lot. If not, we return false; otherwise, we decrement the number of corresponding parking spaces by one and return true.

The time complexity is O(1), and the space complexity is O(1).

PythonJavaC++GoTypeScriptRustC#C
class ParkingSystem: def __init__(self, big: int, medium: int, small: int): self.cnt = [0, big, medium, small] def addCar(self, carType: int) -> bool: if self.cnt[carType] == 0: return False self.cnt[carType] -= 1 return True # Your ParkingSystem object will be instantiated and called as such: # obj = ParkingSystem(big, medium, small) # param_1 = obj.addCar(carType)(code-box)

Post a Comment

0Comments

Post a Comment (0)

#buttons=(Accept !) #days=(20)

Our website uses cookies to enhance your experience. Check Now
Accept !