LeetCode 1555. Bank Account Summary SQL Solution | Explanation + Code

Description

Table: Users

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| user_id      | int     |
| user_name    | varchar |
| credit       | int     |
+--------------+---------+
user_id is the primary key (column with unique values) for this table.
Each row of this table contains the current credit information for each user.

 

Table: Transactions

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| trans_id      | int     |
| paid_by       | int     |
| paid_to       | int     |
| amount        | int     |
| transacted_on | date    |
+---------------+---------+
trans_id is the primary key (column with unique values) for this table.
Each row of this table contains information about the transaction in the bank.
User with id (paid_by) transfer money to user with id (paid_to).

 

Leetcode Bank (LCB) helps its coders in making virtual payments. Our bank records all transactions in the table Transaction, we want to find out the current balance of all users and check whether they have breached their credit limit (If their current credit is less than 0).

Write a solution to report.

• user_id,
• user_name,
• credit, current balance after performing transactions, and
• credit_limit_breached, check credit_limit ("Yes" or "No")

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Users table:
+------------+--------------+-------------+
| user_id    | user_name    | credit      |
+------------+--------------+-------------+
| 1          | Moustafa     | 100         |
| 2          | Jonathan     | 200         |
| 3          | Winston      | 10000       |
| 4          | Luis         | 800         | 
+------------+--------------+-------------+
Transactions table:
+------------+------------+------------+----------+---------------+
| trans_id   | paid_by    | paid_to    | amount   | transacted_on |
+------------+------------+------------+----------+---------------+
| 1          | 1          | 3          | 400      | 2020-08-01    |
| 2          | 3          | 2          | 500      | 2020-08-02    |
| 3          | 2          | 1          | 200      | 2020-08-03    |
+------------+------------+------------+----------+---------------+
Output: 
+------------+------------+------------+-----------------------+
| user_id    | user_name  | credit     | credit_limit_breached |
+------------+------------+------------+-----------------------+
| 1          | Moustafa   | -100       | Yes                   | 
| 2          | Jonathan   | 500        | No                    |
| 3          | Winston    | 9900       | No                    |
| 4          | Luis       | 800        | No                    |
+------------+------------+------------+-----------------------+
Explanation: 
Moustafa paid 400 on "2020-08-01" and received200 on "2020-08-03", credit (100 -400 +200) = -$100
Jonathan received 500 on "2020-08-02" and paid200 on "2020-08-08", credit (200 +500 -200) = $500
Winston received 400 on "2020-08-01" and paid500 on "2020-08-03", credit (10000 +400 -500) = $9990
Luis did not received any transfer, credit = $800

Solutions

Solution 1

sql

# Write your MySQL query statement below SELECT t.user_id, user_name, SUM(t.credit) AS credit, IF(SUM(t.credit) < 0, 'Yes', 'No') AS credit_limit_breached FROM ( SELECT paid_by AS user_id, -amount AS credit FROM Transactions UNION ALL SELECT paid_to AS user_id, amount AS credit FROM Transactions UNION ALL SELECT user_id, credit FROM Users ) AS t JOIN Users AS u ON t.user_id = u.user_id GROUP BY t.user_id;(code-box)