LeetCode 0352. Data Stream as Disjoint Intervals Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0352. Data Stream as Disjoint Intervals

Description

Given a data stream input of non-negative integers a1, a2, ..., an, summarize the numbers seen so far as a list of disjoint intervals.

Implement the SummaryRanges class:

  • SummaryRanges() Initializes the object with an empty stream.
  • void addNum(int value) Adds the integer value to the stream.
  • int[][] getIntervals() Returns a summary of the integers in the stream currently as a list of disjoint intervals [starti, endi]. The answer should be sorted by starti.

 

Example 1:

Input
["SummaryRanges", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals"]
[[], [1], [], [3], [], [7], [], [2], [], [6], []]
Output
[null, null, [[1, 1]], null, [[1, 1], [3, 3]], null, [[1, 1], [3, 3], [7, 7]], null, [[1, 3], [7, 7]], null, [[1, 3], [6, 7]]]

Explanation
SummaryRanges summaryRanges = new SummaryRanges();
summaryRanges.addNum(1);      // arr = [1]
summaryRanges.getIntervals(); // return [[1, 1]]
summaryRanges.addNum(3);      // arr = [1, 3]
summaryRanges.getIntervals(); // return [[1, 1], [3, 3]]
summaryRanges.addNum(7);      // arr = [1, 3, 7]
summaryRanges.getIntervals(); // return [[1, 1], [3, 3], [7, 7]]
summaryRanges.addNum(2);      // arr = [1, 2, 3, 7]
summaryRanges.getIntervals(); // return [[1, 3], [7, 7]]
summaryRanges.addNum(6);      // arr = [1, 2, 3, 6, 7]
summaryRanges.getIntervals(); // return [[1, 3], [6, 7]]

 

Constraints:

  • 0 <= value <= 104
  • At most 3 * 104 calls will be made to addNum and getIntervals.
  • At most 102 calls will be made to getIntervals.

 

Follow up: What if there are lots of merges and the number of disjoint intervals is small compared to the size of the data stream?

Solutions

Solution 1

PythonJavaC++
class SummaryRanges: def __init__(self): self.mp = SortedDict() def addNum(self, val: int) -> None: n = len(self.mp) ridx = self.mp.bisect_right(val) lidx = n if ridx == 0 else ridx - 1 keys = self.mp.keys() values = self.mp.values() if ( lidx != n and ridx != n and values[lidx][1] + 1 == val and values[ridx][0] - 1 == val ): self.mp[keys[lidx]][1] = self.mp[keys[ridx]][1] self.mp.pop(keys[ridx]) elif lidx != n and val <= values[lidx][1] + 1: self.mp[keys[lidx]][1] = max(val, self.mp[keys[lidx]][1]) elif ridx != n and val >= values[ridx][0] - 1: self.mp[keys[ridx]][0] = min(val, self.mp[keys[ridx]][0]) else: self.mp[val] = [val, val] def getIntervals(self) -> List[List[int]]: return list(self.mp.values()) # # Your SummaryRanges object will be instantiated and called as such: # # obj = SummaryRanges() # # obj.addNum(val) # # param_2 = obj.getIntervals()(code-box)

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