LeetCode 0341. Flatten Nested List Iterator Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0341. Flatten Nested List Iterator

Description

You are given a nested list of integers nestedList. Each element is either an integer or a list whose elements may also be integers or other lists. Implement an iterator to flatten it.

Implement the NestedIterator class:

  • NestedIterator(List<NestedInteger> nestedList) Initializes the iterator with the nested list nestedList.
  • int next() Returns the next integer in the nested list.
  • boolean hasNext() Returns true if there are still some integers in the nested list and false otherwise.

Your code will be tested with the following pseudocode:

initialize iterator with nestedList
res = []
while iterator.hasNext()
    append iterator.next() to the end of res
return res

If res matches the expected flattened list, then your code will be judged as correct.

 

Example 1:

Input: nestedList = [[1,1],2,[1,1]]
Output: [1,1,2,1,1]
Explanation: By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1].

Example 2:

Input: nestedList = [1,[4,[6]]]
Output: [1,4,6]
Explanation: By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6].

 

Constraints:

  • 1 <= nestedList.length <= 500
  • The values of the integers in the nested list is in the range [-106, 106].

Solutions

Solution 1

PythonJavaC++GoTypeScriptRust
# """ # This is the interface that allows for creating nested lists. # You should not implement it, or speculate about its implementation # """ # class NestedInteger: # def isInteger(self) -> bool: # """ # @return True if this NestedInteger holds a single integer, rather than a nested list. # """ # # def getInteger(self) -> int: # """ # @return the single integer that this NestedInteger holds, if it holds a single integer # Return None if this NestedInteger holds a nested list # """ # # def getList(self) -> [NestedInteger]: # """ # @return the nested list that this NestedInteger holds, if it holds a nested list # Return None if this NestedInteger holds a single integer # """ class NestedIterator: def __init__(self, nestedList: [NestedInteger]): def dfs(ls): for x in ls: if x.isInteger(): self.nums.append(x.getInteger()) else: dfs(x.getList()) self.nums = [] self.i = -1 dfs(nestedList) def next(self) -> int: self.i += 1 return self.nums[self.i] def hasNext(self) -> bool: return self.i + 1 < len(self.nums) # Your NestedIterator object will be instantiated and called as such: # i, v = NestedIterator(nestedList), [] # while i.hasNext(): v.append(i.next())(code-box)

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