LeetCode 0284. Peeking Iterator Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0284. Peeking Iterator

Description

Design an iterator that supports the peek operation on an existing iterator in addition to the hasNext and the next operations.

Implement the PeekingIterator class:

  • PeekingIterator(Iterator<int> nums) Initializes the object with the given integer iterator iterator.
  • int next() Returns the next element in the array and moves the pointer to the next element.
  • boolean hasNext() Returns true if there are still elements in the array.
  • int peek() Returns the next element in the array without moving the pointer.

Note: Each language may have a different implementation of the constructor and Iterator, but they all support the int next() and boolean hasNext() functions.

 

Example 1:

Input
["PeekingIterator", "next", "peek", "next", "next", "hasNext"]
[[[1, 2, 3]], [], [], [], [], []]
Output
[null, 1, 2, 2, 3, false]

Explanation
PeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [1,2,3]
peekingIterator.next();    // return 1, the pointer moves to the next element [1,2,3].
peekingIterator.peek();    // return 2, the pointer does not move [1,2,3].
peekingIterator.next();    // return 2, the pointer moves to the next element [1,2,3]
peekingIterator.next();    // return 3, the pointer moves to the next element [1,2,3]
peekingIterator.hasNext(); // return False

 

Constraints:

  • 1 <= nums.length <= 1000
  • 1 <= nums[i] <= 1000
  • All the calls to next and peek are valid.
  • At most 1000 calls will be made to next, hasNext, and peek.

 

Follow up: How would you extend your design to be generic and work with all types, not just integer?

Solutions

Solution 1

PythonJavaC++Go
# Below is the interface for Iterator, which is already defined for you. # # class Iterator: # def __init__(self, nums): # """ # Initializes an iterator object to the beginning of a list. # :type nums: List[int] # """ # # def hasNext(self): # """ # Returns true if the iteration has more elements. # :rtype: bool # """ # # def next(self): # """ # Returns the next element in the iteration. # :rtype: int # """ class PeekingIterator: def __init__(self, iterator): """ Initialize your data structure here. :type iterator: Iterator """ self.iterator = iterator self.has_peeked = False self.peeked_element = None def peek(self): """ Returns the next element in the iteration without advancing the iterator. :rtype: int """ if not self.has_peeked: self.peeked_element = self.iterator.next() self.has_peeked = True return self.peeked_element def next(self): """ :rtype: int """ if not self.has_peeked: return self.iterator.next() result = self.peeked_element self.has_peeked = False self.peeked_element = None return result def hasNext(self): """ :rtype: bool """ return self.has_peeked or self.iterator.hasNext() # Your PeekingIterator object will be instantiated and called as such: # iter = PeekingIterator(Iterator(nums)) # while iter.hasNext(): # val = iter.peek() # Get the next element but not advance the iterator. # iter.next() # Should return the same value as [val].(code-box)

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