LeetCode 0282. Expression Add Operators Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0282. Expression Add Operators

Description

Given a string num that contains only digits and an integer target, return all possibilities to insert the binary operators '+', '-', and/or '*' between the digits of num so that the resultant expression evaluates to the target value.

Note that operands in the returned expressions should not contain leading zeros.

Note that a number can contain multiple digits.

 

Example 1:

Input: num = "123", target = 6
Output: ["1*2*3","1+2+3"]
Explanation: Both "1*2*3" and "1+2+3" evaluate to 6.

Example 2:

Input: num = "232", target = 8
Output: ["2*3+2","2+3*2"]
Explanation: Both "2*3+2" and "2+3*2" evaluate to 8.

Example 3:

Input: num = "3456237490", target = 9191
Output: []
Explanation: There are no expressions that can be created from "3456237490" to evaluate to 9191.

 

Constraints:

  • 1 <= num.length <= 10
  • num consists of only digits.
  • -231 <= target <= 231 - 1

Solutions

Solution 1

PythonJavaC#
class Solution: def addOperators(self, num: str, target: int) -> List[str]: ans = [] def dfs(u, prev, curr, path): if u == len(num): if curr == target: ans.append(path) return for i in range(u, len(num)): if i != u and num[u] == '0': break next = int(num[u : i + 1]) if u == 0: dfs(i + 1, next, next, path + str(next)) else: dfs(i + 1, next, curr + next, path + "+" + str(next)) dfs(i + 1, -next, curr - next, path + "-" + str(next)) dfs( i + 1, prev * next, curr - prev + prev * next, path + "*" + str(next), ) dfs(0, 0, 0, "") return ans(code-box)

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