LeetCode 0155. Min Stack Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0155. Min Stack

Description

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

Implement the MinStack class:

  • MinStack() initializes the stack object.
  • void push(int val) pushes the element val onto the stack.
  • void pop() removes the element on the top of the stack.
  • int top() gets the top element of the stack.
  • int getMin() retrieves the minimum element in the stack.

You must implement a solution with O(1) time complexity for each function.

 

Example 1:

Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]

Output
[null,null,null,null,-3,null,0,-2]

Explanation
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top();    // return 0
minStack.getMin(); // return -2

 

Constraints:

  • -231 <= val <= 231 - 1
  • Methods pop, top and getMin operations will always be called on non-empty stacks.
  • At most 3 * 104 calls will be made to push, pop, top, and getMin.

Solutions

Solution 1

PythonJavaC++GoTypeScriptRustJavaScriptC#
class MinStack: def __init__(self): self.stk1 = [] self.stk2 = [inf] def push(self, val: int) -> None: self.stk1.append(val) self.stk2.append(min(val, self.stk2[-1])) def pop(self) -> None: self.stk1.pop() self.stk2.pop() def top(self) -> int: return self.stk1[-1] def getMin(self) -> int: return self.stk2[-1] # Your MinStack object will be instantiated and called as such: # obj = MinStack() # obj.push(val) # obj.pop() # param_3 = obj.top() # param_4 = obj.getMin()(code-box)

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