LeetCode 0133. Clone Graph Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

CoderIndeed
0
0133. Clone Graph

Description

Given a reference of a node in a connected undirected graph.

Return a deep copy (clone) of the graph.

Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.

class Node {
    public int val;
    public List<Node> neighbors;
}

 

Test case format:

For simplicity, each node's value is the same as the node's index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.

An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.

The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.

 

Example 1:

Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Explanation: There are 4 nodes in the graph.
1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).

Example 2:

Input: adjList = [[]]
Output: [[]]
Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.

Example 3:

Input: adjList = []
Output: []
Explanation: This an empty graph, it does not have any nodes.

 

Constraints:

  • The number of nodes in the graph is in the range [0, 100].
  • 1 <= Node.val <= 100
  • Node.val is unique for each node.
  • There are no repeated edges and no self-loops in the graph.
  • The Graph is connected and all nodes can be visited starting from the given node.

Solutions

Solution 1: Hash Table + DFS

We use a hash table g to record the correspondence between each node in the original graph and its copy, and then perform depth-first search.

We define the function dfs(node), which returns the copy of the node. The process of dfs(node) is as follows:

  • If node is null, then the return value of dfs(node) is null.
  • If node is in g, then the return value of dfs(node) is g[node].
  • Otherwise, we create a new node cloned and set the value of g[node] to cloned. Then, we traverse all the neighbor nodes nxt of node and add dfs(nxt) to the neighbor list of cloned.
  • Finally, return cloned.

In the main function, we return dfs(node).

The time complexity is O(n), and the space complexity is O(n). Here, n is the number of nodes.

PythonJavaC++GoTypeScriptJavaScriptC#
""" # Definition for a Node. class Node: def __init__(self, val = 0, neighbors = None): self.val = val self.neighbors = neighbors if neighbors is not None else [] """ from typing import Optional class Solution: def cloneGraph(self, node: Optional["Node"]) -> Optional["Node"]: def dfs(node): if node is None: return None if node in g: return g[node] cloned = Node(node.val) g[node] = cloned for nxt in node.neighbors: cloned.neighbors.append(dfs(nxt)) return cloned g = defaultdict() return dfs(node)(code-box)

Post a Comment

0Comments

Post a Comment (0)

#buttons=(Accept !) #days=(20)

Our website uses cookies to enhance your experience. Check Now
Accept !