LeetCode 2754. Bind Function to Context TypeScript Solution | Explanation + Code

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2754. Bind Function to Context

Description

Enhance all functions to have the bindPolyfill method. When bindPolyfill is called with a passed object obj, that object becomes the this context for the function.

For example, if you had the code:

function f() {
  console.log('My context is ' + this.ctx);
}
f();

The output would be "My context is undefined". However, if you bound the function:

function f() {
  console.log('My context is ' + this.ctx);
}
const boundFunc = f.boundPolyfill({ "ctx": "My Object" })
boundFunc();

The output should be "My context is My Object".

You may assume that a single non-null object will be passed to the bindPolyfill method.

Please solve it without the built-in Function.bind method.

 

Example 1:

Input: 
fn = function f(multiplier) { 
  return this.x * multiplier; 
}
obj = {"x": 10}
inputs = [5]
Output: 50
Explanation:
const boundFunc = f.bindPolyfill({"x": 10});
boundFunc(5); // 50
A multiplier of 5 is passed as a parameter.
The context is set to {"x": 10}.
Multiplying those two numbers yields 50.

Example 2:

Input: 
fn = function speak() { 
  return "My name is " + this.name; 
}
obj = {"name": "Kathy"}
inputs = []
Output: "My name is Kathy"
Explanation:
const boundFunc = f.bindPolyfill({"name": "Kathy"});
boundFunc(); // "My name is Kathy"

 

Constraints:

  • obj is a non-null object
  • 0 <= inputs.length <= 100

 

Can you solve it without using any built-in methods?

Solutions

Solution 1

TypeScript
type Fn = (...args) => any; declare global { interface Function { bindPolyfill(obj: Record<any, any>): Fn; } } Function.prototype.bindPolyfill = function (obj) { return (...args) => { return this.call(obj, ...args); }; };(code-box)

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