Description
Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.
Note that minor deviation from millis in the actual sleep duration is acceptable.
Example 1:
Input: millis = 100
Output: 100
Explanation: It should return a promise that resolves after 100ms.
let t = Date.now();
sleep(100).then(() => {
console.log(Date.now() - t); // 100
});
Example 2:
Input: millis = 200 Output: 200 Explanation: It should return a promise that resolves after 200ms.
Constraints:
1 <= millis <= 1000
Solutions
Solution 1
TypeScriptJavaScript
async function sleep(millis: number): Promise<void> { return new Promise(r => setTimeout(r, millis)); } /** * let t = Date.now() * sleep(100).then(() => console.log(Date.now() - t)) // 100 */(code-box)
