LeetCode 2579. Count Total Number of Colored Cells Solution in Java, C++, Python & More | Explanation + Code

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2579. Count Total Number of Colored Cells

Description

There exists an infinitely large two-dimensional grid of uncolored unit cells. You are given a positive integer n, indicating that you must do the following routine for n minutes:

  • At the first minute, color any arbitrary unit cell blue.
  • Every minute thereafter, color blue every uncolored cell that touches a blue cell.

Below is a pictorial representation of the state of the grid after minutes 1, 2, and 3.

Return the number of colored cells at the end of n minutes.

 

Example 1:

Input: n = 1
Output: 1
Explanation: After 1 minute, there is only 1 blue cell, so we return 1.

Example 2:

Input: n = 2
Output: 5
Explanation: After 2 minutes, there are 4 colored cells on the boundary and 1 in the center, so we return 5. 

 

Constraints:

  • 1 <= n <= 105

Solutions

Solution 1: Mathematics

We find that after the nth minute, there are a total of 2 × n - 1 columns in the grid, and the numbers on each column are respectively 1, 3, 5, …, 2 × n - 1, 2 × n - 3, …, 3, 1. The left and right parts are both arithmetic progressions, and the sum can be obtained by 2 × n × (n - 1) + 1.

The time complexity is O(1), and the space complexity is O(1).

PythonJavaC++GoTypeScriptRust
class Solution: def coloredCells(self, n: int) -> int: return 2 * n * (n - 1) + 1(code-box)

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