Description
Given an integer array nums that does not contain any zeros, find the largest positive integer k such that -k also exists in the array.
Return the positive integer k. If there is no such integer, return -1.
Example 1:
Input: nums = [-1,2,-3,3] Output: 3 Explanation: 3 is the only valid k we can find in the array.
Example 2:
Input: nums = [-1,10,6,7,-7,1] Output: 7 Explanation: Both 1 and 7 have their corresponding negative values in the array. 7 has a larger value.
Example 3:
Input: nums = [-10,8,6,7,-2,-3] Output: -1 Explanation: There is no a single valid k, we return -1.
Constraints:
1 <= nums.length <= 1000-1000 <= nums[i] <= 1000nums[i] != 0
Solutions
Solution 1: Hash Table
We can use a hash table s to record all elements that appear in the array, and a variable ans to record the maximum positive integer that satisfies the problem requirements, initially ans = -1.
Next, we traverse each element x in the hash table s. If -x exists in s, then we update ans = max(ans, x).
After the traversal ends, return ans.
The time complexity is O(n), and the space complexity is O(n). Here, n is the length of the array.
PythonJavaC++GoTypeScriptRust
class Solution: def findMaxK(self, nums: List[int]) -> int: s = set(nums) return max((x for x in s if -x in s), default=-1)(code-box)
Solution 2
Rust
use std::collections::HashSet; impl Solution { pub fn find_max_k(nums: Vec<i32>) -> i32 { let mut ans = -1; let mut h = HashSet::new(); for &n in &nums { h.insert(n); } for &n in &nums { if h.contains(&-n) && n > ans { ans = n; } } ans } }(code-box)
