Description
Given a date string in the form Day Month Year, where:
Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.Year is in the range [1900, 2100].
Convert the date string to the format YYYY-MM-DD, where:
YYYY denotes the 4 digit year.MM denotes the 2 digit month.DD denotes the 2 digit day.
Example 1:
Input: date = "20th Oct 2052"
Output: "2052-10-20"
Example 2:
Input: date = "6th Jun 1933"
Output: "1933-06-06"
Example 3:
Input: date = "26th May 1960"
Output: "1960-05-26"
Constraints:
- The given dates are guaranteed to be valid, so no error handling is necessary.
Solutions
Solution 1
PythonJavaC++GoTypeScriptPHP
class Solution:
def reformatDate(self, date: str) -> str:
s = date.split()
s.reverse()
months = " JanFebMarAprMayJunJulAugSepOctNovDec"
s[1] = str(months.index(s[1]) // 3 + 1).zfill(2)
s[2] = s[2][:-2].zfill(2)
return "-".join(s)(code-box)
class Solution {
public String reformatDate(String date) {
var s = date.split(" ");
String months = " JanFebMarAprMayJunJulAugSepOctNovDec";
int day = Integer.parseInt(s[0].substring(0, s[0].length() - 2));
int month = months.indexOf(s[1]) / 3 + 1;
return String.format("%s-%02d-%02d", s[2], month, day);
}
}(code-box)
class Solution {
public:
string reformatDate(string date) {
string months = " JanFebMarAprMayJunJulAugSepOctNovDec";
stringstream ss(date);
string year, month, t;
int day;
ss >> day >> t >> month >> year;
month = to_string(months.find(month) / 3 + 1);
return year + "-" + (month.size() == 1 ? "0" + month : month) + "-" + (day > 9 ? "" : "0") + to_string(day);
}
};(code-box)
func reformatDate(date string) string {
s := strings.Split(date, " ")
day, _ := strconv.Atoi(s[0][:len(s[0])-2])
months := " JanFebMarAprMayJunJulAugSepOctNovDec"
month := strings.Index(months, s[1])/3 + 1
year, _ := strconv.Atoi(s[2])
return fmt.Sprintf("%d-%02d-%02d", year, month, day)
}(code-box)
function reformatDate(date: string): string {
const s = date.split(' ');
const months = ' JanFebMarAprMayJunJulAugSepOctNovDec';
const day = parseInt(s[0].substring(0, s[0].length - 2));
const month = Math.floor(months.indexOf(s[1]) / 3) + 1;
return `${s[2]}-${month.toString().padStart(2, '0')}-${day.toString().padStart(2, '0')}`;
}(code-box)
class Solution {
/**
* @param String $date
* @return String
*/
function reformatDate($date) {
$arr = explode(' ', $date);
$months = [
'Jan' => '01',
'Feb' => '02',
'Mar' => '03',
'Apr' => '04',
'May' => '05',
'Jun' => '06',
'Jul' => '07',
'Aug' => '08',
'Sep' => '09',
'Oct' => '10',
'Nov' => '11',
'Dec' => '12',
];
$year = $arr[2];
$month = $months[$arr[1]];
$day = intval($arr[0]);
if ($day > 0 && $day < 10) {
$day = '0' . $day;
}
return $year . '-' . $month . '-' . $day;
}
}(code-box)
