Description
You are given an integer array nums. You want to maximize the number of points you get by performing the following operation any number of times:
- Pick any
nums[i]and delete it to earnnums[i]points. Afterwards, you must delete every element equal tonums[i] - 1and every element equal tonums[i] + 1.
Return the maximum number of points you can earn by applying the above operation some number of times.
Example 1:
Input: nums = [3,4,2] Output: 6 Explanation: You can perform the following operations: - Delete 4 to earn 4 points. Consequently, 3 is also deleted. nums = [2]. - Delete 2 to earn 2 points. nums = []. You earn a total of 6 points.
Example 2:
Input: nums = [2,2,3,3,3,4] Output: 9 Explanation: You can perform the following operations: - Delete a 3 to earn 3 points. All 2's and 4's are also deleted. nums = [3,3]. - Delete a 3 again to earn 3 points. nums = [3]. - Delete a 3 once more to earn 3 points. nums = []. You earn a total of 9 points.
Constraints:
1 <= nums.length <= 2 * 1041 <= nums[i] <= 104
Solutions
Solution 1
PythonJavaC++Go
class Solution: def deleteAndEarn(self, nums: List[int]) -> int: mx = -inf for num in nums: mx = max(mx, num) total = [0] * (mx + 1) for num in nums: total[num] += num first = total[0] second = max(total[0], total[1]) for i in range(2, mx + 1): cur = max(first + total[i], second) first = second second = cur return second(code-box)
