LeetCode 0740. Delete and Earn Solution in Java, C++, Python & Go | Explanation + Code

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0740. Delete and Earn

Description

You are given an integer array nums. You want to maximize the number of points you get by performing the following operation any number of times:

  • Pick any nums[i] and delete it to earn nums[i] points. Afterwards, you must delete every element equal to nums[i] - 1 and every element equal to nums[i] + 1.

Return the maximum number of points you can earn by applying the above operation some number of times.

 

Example 1:

Input: nums = [3,4,2]
Output: 6
Explanation: You can perform the following operations:
- Delete 4 to earn 4 points. Consequently, 3 is also deleted. nums = [2].
- Delete 2 to earn 2 points. nums = [].
You earn a total of 6 points.

Example 2:

Input: nums = [2,2,3,3,3,4]
Output: 9
Explanation: You can perform the following operations:
- Delete a 3 to earn 3 points. All 2's and 4's are also deleted. nums = [3,3].
- Delete a 3 again to earn 3 points. nums = [3].
- Delete a 3 once more to earn 3 points. nums = [].
You earn a total of 9 points.

 

Constraints:

  • 1 <= nums.length <= 2 * 104
  • 1 <= nums[i] <= 104

Solutions

Solution 1

PythonJavaC++Go
class Solution: def deleteAndEarn(self, nums: List[int]) -> int: mx = -inf for num in nums: mx = max(mx, num) total = [0] * (mx + 1) for num in nums: total[num] += num first = total[0] second = max(total[0], total[1]) for i in range(2, mx + 1): cur = max(first + total[i], second) first = second second = cur return second(code-box)

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