LeetCode 0622. Design Circular Queue Solution in Java, C++, Python & More | Explanation + Code

CoderIndeed
0
0622. Design Circular Queue

Description

Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle, and the last position is connected back to the first position to make a circle. It is also called "Ring Buffer".

One of the benefits of the circular queue is that we can make use of the spaces in front of the queue. In a normal queue, once the queue becomes full, we cannot insert the next element even if there is a space in front of the queue. But using the circular queue, we can use the space to store new values.

Implement the MyCircularQueue class:

  • MyCircularQueue(k) Initializes the object with the size of the queue to be k.
  • int Front() Gets the front item from the queue. If the queue is empty, return -1.
  • int Rear() Gets the last item from the queue. If the queue is empty, return -1.
  • boolean enQueue(int value) Inserts an element into the circular queue. Return true if the operation is successful.
  • boolean deQueue() Deletes an element from the circular queue. Return true if the operation is successful.
  • boolean isEmpty() Checks whether the circular queue is empty or not.
  • boolean isFull() Checks whether the circular queue is full or not.

You must solve the problem without using the built-in queue data structure in your programming language. 

 

Example 1:

Input
["MyCircularQueue", "enQueue", "enQueue", "enQueue", "enQueue", "Rear", "isFull", "deQueue", "enQueue", "Rear"]
[[3], [1], [2], [3], [4], [], [], [], [4], []]
Output
[null, true, true, true, false, 3, true, true, true, 4]

Explanation
MyCircularQueue myCircularQueue = new MyCircularQueue(3);
myCircularQueue.enQueue(1); // return True
myCircularQueue.enQueue(2); // return True
myCircularQueue.enQueue(3); // return True
myCircularQueue.enQueue(4); // return False
myCircularQueue.Rear();     // return 3
myCircularQueue.isFull();   // return True
myCircularQueue.deQueue();  // return True
myCircularQueue.enQueue(4); // return True
myCircularQueue.Rear();     // return 4

 

Constraints:

  • 1 <= k <= 1000
  • 0 <= value <= 1000
  • At most 3000 calls will be made to enQueue, deQueueFrontRearisEmpty, and isFull.

Solutions

Solution 1: Array Simulation

We can use an array q of length k to simulate a circular queue, with a pointer front to record the position of the front element. Initially, the queue is empty, and front is 0. Additionally, we use a variable size to record the number of elements in the queue, initially size is 0.

When calling the enQueue method, we first check if the queue is full, i.e., size = k. If it is full, we return false. Otherwise, we insert the element at position (front + size) \bmod k, then size = size + 1, indicating that the number of elements in the queue has increased by 1. Finally, we return true.

When calling the deQueue method, we first check if the queue is empty, i.e., size = 0. If it is empty, we return false. Otherwise, we set front = (front + 1) \bmod k, indicating that the front element has been dequeued, then size = size - 1.

When calling the Front method, we first check if the queue is empty, i.e., size = 0. If it is empty, we return -1. Otherwise, we return q[front].

When calling the Rear method, we first check if the queue is empty, i.e., size = 0. If it is empty, we return -1. Otherwise, we return q[(front + size - 1) \bmod k].

When calling the isEmpty method, we simply check if size = 0.

When calling the isFull method, we simply check if size = k.

In terms of time complexity, the above operations all have a time complexity of O(1). The space complexity is O(k).

PythonJavaC++GoTypeScriptRust
class MyCircularQueue: def __init__(self, k: int): self.q = [0] * k self.size = 0 self.capacity = k self.front = 0 def enQueue(self, value: int) -> bool: if self.isFull(): return False self.q[(self.front + self.size) % self.capacity] = value self.size += 1 return True def deQueue(self) -> bool: if self.isEmpty(): return False self.front = (self.front + 1) % self.capacity self.size -= 1 return True def Front(self) -> int: return -1 if self.isEmpty() else self.q[self.front] def Rear(self) -> int: if self.isEmpty(): return -1 return self.q[(self.front + self.size - 1) % self.capacity] def isEmpty(self) -> bool: return self.size == 0 def isFull(self) -> bool: return self.size == self.capacity # Your MyCircularQueue object will be instantiated and called as such: # obj = MyCircularQueue(k) # param_1 = obj.enQueue(value) # param_2 = obj.deQueue() # param_3 = obj.Front() # param_4 = obj.Rear() # param_5 = obj.isEmpty() # param_6 = obj.isFull()(code-box)

Post a Comment

0Comments

Post a Comment (0)

#buttons=(Accept !) #days=(20)

Our website uses cookies to enhance your experience. Check Now
Accept !