LeetCode 0150. Evaluate Reverse Polish Notation Solution in Java, Python, C++, JavaScript, Go & Rust | Explanation + Code

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0150. Evaluate Reverse Polish Notation

Description

You are given an array of strings tokens that represents an arithmetic expression in a Reverse Polish Notation.

Evaluate the expression. Return an integer that represents the value of the expression.

Note that:

  • The valid operators are '+', '-', '*', and '/'.
  • Each operand may be an integer or another expression.
  • The division between two integers always truncates toward zero.
  • There will not be any division by zero.
  • The input represents a valid arithmetic expression in a reverse polish notation.
  • The answer and all the intermediate calculations can be represented in a 32-bit integer.

 

Example 1:

Input: tokens = ["2","1","+","3","*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9

Example 2:

Input: tokens = ["4","13","5","/","+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6

Example 3:

Input: tokens = ["10","6","9","3","+","-11","*","/","*","17","+","5","+"]
Output: 22
Explanation: ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22

 

Constraints:

  • 1 <= tokens.length <= 104
  • tokens[i] is either an operator: "+", "-", "*", or "/", or an integer in the range [-200, 200].

Solutions

Solution 1

PythonJavaC++GoTypeScriptRustC#
import operator class Solution: def evalRPN(self, tokens: List[str]) -> int: opt = { "+": operator.add, "-": operator.sub, "*": operator.mul, "/": operator.truediv, } s = [] for token in tokens: if token in opt: s.append(int(opt[token](s.pop(-2), s.pop(-1)))) else: s.append(int(token)) return s[0](code-box)

Solution 2

Python
class Solution: def evalRPN(self, tokens: List[str]) -> int: nums = [] for t in tokens: if len(t) > 1 or t.isdigit(): nums.append(int(t)) else: if t == "+": nums[-2] += nums[-1] elif t == "-": nums[-2] -= nums[-1] elif t == "*": nums[-2] *= nums[-1] else: nums[-2] = int(nums[-2] / nums[-1]) nums.pop() return nums[0](code-box)

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